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Julabo
Determination of Heating/Cooling Power

The following is the general formula for determining necessary heating and cooling requirements of a system.  
Formula:  Q=mC(T2-T1)/t 

where:

m=

mass of bath/reactor fluid      
 

C=

specific heat of bath/reactor fluid    
 

T1=

start temperature        
 

T2=

end temperature        
 

t=

elapsed time        
Directions: Please substitute your own values as indicated below.        
                   

Value

                 
1 20 liters Enter the volume of the circulator + hoses + reactor jacket volume
2 0 liters Enter the volume of the reactor (enter zero if not applicable)
3 1 kg/liter Enter the density of the circulator bath fluid
4 0 kg/liter Enter the density of the reactor fluid (enter zero if not applicable)
5 1.45 kJ/(kg°C) Enter the specific heat capacity of the circulator bath fluid
6 0 kJ/(kg°C) Enter the specific heat capacity of the reactor fluid (zero if not applicable)
7 120 °C Enter the starting temperature 
8 -10 °C Enter the target temperature
9 14000 seconds Enter the desired heat-up/cool-down time 
10   kW Enter estimated power losses (this number must be positive)
                   
    Bath Liquid Properties        
Value m1(kg)                
11

20

Multiply value 1 times value 3 and enter result here    
                   
  C1 (kJ/[kg°C])                
12

1.45

Enter value 5 here       Reference Data
                   
    Reactor Liquid Properties   Specific Heat Density
  m2 (kg)             kJ/(kg°C) kg/liter
13

      

Multiply value 2 times value 4 and enter result here water 4.18 1
              ethanol 2.43 0.783
  C2 (kJ/[kg°C])           methanol 2.49 0.787
14

      

Enter value 6 here     silicon oil 1.45 1
                aluminum 0.896 2.7
    Customer Requirements   copper 0.385 8.9
Value t (s)           iron 0.45 7.84
15

14000

Enter value 9 here     lead 0.128 11.31
              silver 0.235 10.47
  T1 (°C)           tin 0.217 5.73
16

120

Enter value 7 here     ammonia 4.8 0.602
              mercury 0.139 13.56
  T2 (°C)           50/50 EG/H20 3.25 1.1
17

-10

Enter value 8 here          
                   
Required Heating/Cooling Power   Modified Equation:    
        Q=[(m1C1)+(m2C2)][(DT)/t]    
  Temperature Change              
Value DT (°C)                
18

-130

Subtract value 16 from value 17 and enter result here    
                   
19 Nominal Heat Load (kW) Nominal Heat Load is the calculated load based on the customer's requirements.
 

-0.269

Perform the following calculation:  [(v11v12)+(v13v14)][(v18)/v15]  
20 Total Heat Load (kW) Total Heat Load is the Nominal Heat Load plus any estimated losses.  
 

-0.269

If value 19 is positive, add value 10.  If value 19 is negative, subtract value 10.
                   
  Heating or Cooling?              
20

Cooling!

If value 19 is positive, heating is required.  If value is negative, cooling is required.
                   
Important Note:  This calculation should only be used as a basis for circulator/chiller selection.  Many factors that will influence power requirements are too difficult to quantify, and thus are neglected from this calculation.  Actual power requirements will almost always be larger than calculated values.
                   
Additional Notes:                
1 Julabo is not responsible for damages/injuries caused by using unapproved bath fluids in circulators/baths/chillers.
2 Julabo is not responsible for damages/injuries resulting from incorrect use of approved bath fluids.
3 Flash points of bath fluids must be above +60°C for transport by plane.
4 Julabo chiller/circulator high temperature warning and safety values should reference fluid flash temperature.
5 Julabo chiller/circulator low temperature warning should reference fluid freezing point or maximum viscosity.
6 Julabo H350 bath oil is intended only for Julabo high temperature sealed systems.

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